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Highway Engineering PYQ – TN TRB Lecturer


11. If the radius of the horizontal curve is 80 mts, design speed is 40 kmph and design coefficient of lateral friction is 0.15, then rate of superelevation of full lateral friction will be _____ .

[TN TRB 2012: 2 Marks]

  1. 0.30
  2. 0.48
  3. 0.60
  4. 0.72
Answer: Option D
Explanation:
Design speed, v = 40 kmph (or) 11.11 m/s

e + f   =  

v2

gR

⇒ e + 0.15   =  

112

9.81 x 80

⇒ e = 0.00728 m (or) 0.728 cm


12. An ascending gradient of 1 in 100 meets a descending gradient of 1 in 50. The length of summit curve required to provide an over turning sight distance of 500 m will be _____ .

[TN TRB 2012: 2 Marks]

  1. 938.25 m
  2. 781.25 m
  3. 470.25 m
  4. 170.25 m
Answer: Option B
Explanation:

N1 =

1

100

, N2 = –

1

50

Deviation Angle, N = |N1 – N2| = |(1/100) – (-1/50)| = 0.03
Assume that length of summit curve (L) > Overtaking sight distance (S), then

L =

NS2

2 H 2 + 2 h 2

⇒ L =

0.03 x 5002

2 1.2 2 + 2 1.2 2

⇒ L = 781.25 m > 500 m
Here, the assumed condition is correct. Hence, the length of summit curve = 781.25 m


13.  In the abrasion test loss in weight is 27 gms, then coefficient of hardness will be _____ .

[TN TRB 2012: 2 Marks]

  1. 11
  2. 12
  3. 13
  4. 14
Answer: Option A

Explanation:

Coefficient of hardness = 20 –  

Loss in weight (gm)

3

  = 20 –

27

3

⇒ Coefficient of hardness = 20 – 9 = 11


14.  The true bearing of a line is 34°20’ and the magnetic declination at that place of observation is 2°20’ west on the date of observation. The magnetic bearing of the line is _____ .

[TN TRB 2012: 2 Marks]

  1. 36°40’
  2. 34°20’
  3. 32°
  4. 32°40’
Answer: Option A
Explanation:
True Bearing = Magnetic Bearing (MB) ± Magnetic Declination
Westward declination is considered to be negative.
Hence, True bearing = Magnetic Bearing – Magnetic Declination
⇒ 34°20’ = MB – 2°20’
⇒ MB = 36°40’

15.  A 30 m metric chain is found to be 0.1 m too short throughout the measurement. If the distance measured is recorded as 300 m, then the actual distance will be _____ .

[TN TRB 2012: 2 Marks]

  1. 300.1 m
  2. 301.0 m
  3. 299.0 m
  4. 310.0 m
Answer: Option C
Explanation:
Nominal length of chain, l = 30 m
Actual length of chain, l’ = 29.9 m
Measured distance, L’ = 300 m

Thus, correct distance, L =

l1

l

  x L’

⇒ L =

29.9

30

 x 300

⇒ L= 299 m


16.  The highway bridges shall not be considered to be carrying any live load when the wind velocity at deck level exceeds _____ .

[TN TRB 2017: 1 Mark]

  1. 50 km/hr
  2. 70km/hr
  3. 100 km/hr
  4. 130 km/hr
Answer: Option D
Explanation:
As per IRC 6:2014 Clause 209.3.7, The bridges shall not be considered to be carrying any live load when the wind speed at deck level exceeds 36 m/s (≈ 129.6 km/hr).

17.  The Nagpur road plan formula was prepared assuming a shape of _____ .

[TN TRB 2017: 1 Mark]

  1. Star and Square pattern
  2. Star and Grid pattern
  3. Star and Circular pattern
  4. Star and Rectangular pattern
Answer: Option B
Explanation:
Star and Grid pattern was adopted as the road pattern as per Nagpur road plan.

18.  Equation for the length of the transition curve for plain and rolling terrain is _____ .

[TN TRB 2017: 1 Mark]

  1. Ls = 3.7 V2
  2. Ls = 4.7 V2
  3. Ls = 2.7 V2
  4. Ls = 1.7 V2
Answer: Option C
Explanation:
As per IRC, Empirical formula for calculating the length of transition curve for plain and rolling terrain is

Ls = 2.7

V2

R

Where,
V – Design speed in km/hr
R – Radius of circular curve in m


19.  The instantaneous speed of a vehicle at a specified location is _____ .

[TN TRB 2017: 1 Mark]

  1. High speed
  2. Slow speed
  3. Spot speed
  4. Over speed
Answer: Option C
Explanation:
Spot speed is defined as the instantaneous speed of a vehicle at a specified location.

20.  The least count of standard vernier Theodolite is _____ .

[TN TRB 2017: 1 Mark]

  1. 40 seconds
  2. 30 seconds
  3. 10 seconds
  4. 20 seconds
Answer: Option D
Explanation:
The least count of a vernier theodolite is between 10” and 20”. The most common vernier theodolite has a least count of 20”.
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