Home » TN TRB » Highway Engineering PYQ ​

Highway Engineering PYQ – TN TRB Lecturer

      

1. In water bound roads binding material is _____ .

[TN TRB 2012: 1 Mark]

  1. Sand
  2. Stone dust
  3. Cement
  4. Brick dust
Answer: Option B
Explanation:
Binding material used in water bound roads must be fine grained to prevent the raveling of the stones. Kankar nodules or limestone dust can be used for this purpose.

2. If L is the length of a moving vehicle and R is the radius of curvature the extra mechanical widening to be provided on horizontal curves for single lane is _____ .

[TN TRB 2012: 1 Mark]

  1. L/2R
  2. L2/2R
  3. L3/2R
  4. 2L/R2
Answer: Option B
Explanation:
Extra Mechanical Widening, Wem = nL2/ 2R
Where,
n – Number of lanes. For single lane, n = 1.
Thus, Wem = nL2/ 2R
⇒Wem = L2/ 2R

3.  According to IRC the maximum super elevation in rolling terrain in plains is limited to _____ .

[TN TRB 2012: 1 Mark]

  1. 4%
  2. 7%
  3. 10%
  4. 5%
Answer: Option B

Explanation:
As per IRC,

  • The maximum super elevation that can be provided in plain and rolling terrain is 7%.
  • The maximum super elevation that can be provided in hilly terrain is 10%.
  • The maximum super elevation that can be provided in urban roads is 4%.

4.  In which of the following traffic signal systems, cycle lengths and cycle division automatically varied?

[TN TRB 2012: 1 Mark]

  1. Simultaneous system
  2. Alternate system
  3. Simple progressive system
  4. Flexible progressive system
Answer: Option D
Explanation:
In a flexible progressive system, it is possible to automatically vary the length of cycle, cycle division and the time schedule at each signalized intersection using a computer.

5.  The drain which is provided parallel to loading to intercept and divert the water from hill slopes is called _____ .

[TN TRB 2012: 1 Mark]

  1. Slope drain
  2. Catch water drain
  3. Side drain
  4. cross-drain
Answer: Option B
Explanation:
Catch water drain runs parallel to the roadway and diverts water from hill slopes.

6.  If θ is the angle of slope, L is the length of slope and h is the difference in elevation between two ends of the line, then slope correction will be _____ .

[TN TRB 2012: 1 Mark]

  1. L sin θ
  2. 2L sin2 (θ/2)
  3. L sin (θ/2)
  4. 2L sin 2θ
Answer: Option B
Explanation:
Slope correction, Cs = – L (1 – Cos θ)
⇒ Cs = – L 2Sin2 (θ/2)
⇒ Cs = – 2L Sin2 (θ/2)
Since, the slope distance will always be more than the horizontal distance, the slope correction is always negative.

7.  Isogonic lines are lines passing through _____ .

[TN TRB 2012: 1 Mark]

  1. Points having same declination 
  2. Points of zero declination
  3. Points having same dip
  4. Points having zero dip
Answer: Option A
Explanation:

  • The lines connecting the points having the same magnetic dip are isoclinic lines.
  • The lines connecting the points having zero magnetic dip are aclinic lines.
  • The lines connecting the points having the same magnetic declination are isogonic lines.
  • The lines connecting the points having zero magnetic declination are agonic lines.

8.  Spire test is used for adjustment of _____ .

[TN TRB 2012: 1 Mark]

  1. Line of sight
  2. Horizontal axis
  3. Vertical axis
  4. Adjustments of altitude bubble
Answer: Option B
Explanation:
Spire test is used to ensure that the horizontal axis is truly horizontal.

9.  Size of a theodolite is specified by _____ .

[TN TRB 2012: 1 Mark]

  1. Diameter of lower plate
  2. Diameter of upper plate
  3. Length of telescope
  4. Diameter of vertical circle
Answer: Option A
Explanation:
The diameter of the lower plate is used to specify the size of theodolite. An 8 cm theodolite represents that the graduated circle of the lower plate is of 8 cm diameter.

10.  If Δ is the angle of deflection of a simple curve of radius R, the length of the curve is _____ .

[TN TRB 2012: 1 Mark]

  1. πRΔ/90
  2. πRΔ/180
  3. πRΔ/270
  4. πRΔ/360
Answer: Option B
Explanation:

Length of the curve, l =

2πR 360°

 x Δ

Pages: 1 2 3 4 5
Scroll to Top