Fluid Mechanics and Machines & Hydrology PYQ – TN TRB Lecturer


41. Rainfall intensity of 20 mm/hr occurred over a watershed of area 100 ha for a duration of 6 hr. Measured Direct Runoff volume in the stream draining the watershed was found to be 30000 m3. The precipitation not available to runoff in this case is _____ .

[TN TRB 2021: 2 Marks]

  1. 9 cm
  2. 3 cm
  3. 17.5 mm
  4. 5 mm
Answer: Option A
Explanation:
Total Rainfall = 20 x 6 = 120 mm

Direct Runoff =

Direct Runoff Volume

Watershed area

=

30000

100 x 104

= 0.03 m (or) 30 mm

Thus, the precipitation not available for runoff = Total Rainfall – Direct Runoff = 120 – 30 = 90 mm (or) 9 cm


42. In the Muskingum method of channel routing, if the coefficients k = 12 hr, x = 0.15 and the time step for routing Δt = 4 hr, then the coefficient C0 is _____ .

[TN TRB 2021: 2 Marks]

  1. 0.656
  2. 0.328
  3. 0.048
  4. 0.016
Answer: Option D
Explanation:

C0 =

-Kx + 0.5Δt

K(1 – x) + 0.5Δt

⇒ C0 =

-(12 x 0.15) + (0.5 x 4)

12 (1 – 0.15) + (0.5 x 4)

⇒ C0 = 0.016


43.  A rectangular plate 3 m long and 1 m wide is immersed vertically in water in such a way that it’s 3 m side is parallel to the water surface and is 1 m below it. The total pressure on the plate is _____ .

[TN TRB 2021: 2 Marks]

  1. 44.14 kN
  2. 34.14 kN
  3. 24.14 kN
  4. 14.14 kN
Answer: Option A
Explanation:

Centroid, h = 1 + (1/2) = 1.5 m
Total pressure, F = ρgAh = 1000 x 9.81 x (3 x 1) x 1.5
⇒ F = 44145 N (or) 44.145 kN

44.  If the x-component of velocity u = 6xy – 2x2 in a possible case of flow, the y-component of the flow v is _____ .

[TN TRB 2021: 2 Marks]

  1. 6y2 – 4xy
  2. -6xy + 2x2
  3. 6x2 – 2xy
  4. 4xy – 3y2
Answer: Option D
Explanation:

u = 6xy – 2x2

∂u

∂x

= 6y – 4x

For a possible case of flow, a continuity equation must exist.

∂u

∂x

+

∂v

∂y

= 0

⇒ 6y – 4x +

∂v

∂y

= 0

∂v

∂y

= 4x – 6y

Integrating with respect to y,

⇒ v = 4xy –

6y2

2

⇒ v = 4xy – 3y2


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